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X^(2)=4-6X

We move all terms to the left:

X^(2)-(4-6X)=0

We add all the numbers together, and all the variables

X^2-(-6X+4)=0

We get rid of parentheses

X^2+6X-4=0

a = 1; b = 6; c = -4;

Δ = b^{2}-4ac

Δ = 6^{2}-4·1·(-4)

Δ = 52

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{13}}{2*1}=\frac{-6-2\sqrt{13}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{13}}{2*1}=\frac{-6+2\sqrt{13}}{2} $

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