9x^2-1800=0

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Solution for 9x^2-1800=0 equation:



9x^2-1800=0
a = 9; b = 0; c = -1800;
Δ = b2-4ac
Δ = 02-4·9·(-1800)
Δ = 64800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{64800}=\sqrt{32400*2}=\sqrt{32400}*\sqrt{2}=180\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180\sqrt{2}}{2*9}=\frac{0-180\sqrt{2}}{18} =-\frac{180\sqrt{2}}{18} =-10\sqrt{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180\sqrt{2}}{2*9}=\frac{0+180\sqrt{2}}{18} =\frac{180\sqrt{2}}{18} =10\sqrt{2} $

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