8w^2+8w+9w=2w=2

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Solution for 8w^2+8w+9w=2w=2 equation:



8w^2+8w+9w=2w=2
We move all terms to the left:
8w^2+8w+9w-(2w)=0
We add all the numbers together, and all the variables
8w^2+15w=0
a = 8; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·8·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*8}=\frac{-30}{16} =-1+7/8 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*8}=\frac{0}{16} =0 $

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