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7m^2-21m-70=0

a = 7; b = -21; c = -70;

Δ = b^{2}-4ac

Δ = -21^{2}-4·7·(-70)

Δ = 2401

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-49}{2*7}=\frac{-28}{14} =-2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+49}{2*7}=\frac{70}{14} =5 $

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