60x-0.4x^2+5x+14=0

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Solution for 60x-0.4x^2+5x+14=0 equation:

60x-0.4x^2+5x+14=0
We add all the numbers together, and all the variables
-0.4x^2+65x+14=0
a = -0.4; b = 65; c = +14;
Δ = b2-4ac
Δ = 652-4·(-0.4)·14
Δ = 4247.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-\sqrt{4247.4}}{2*-0.4}=\frac{-65-\sqrt{4247.4}}{-0.8}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+\sqrt{4247.4}}{2*-0.4}=\frac{-65+\sqrt{4247.4}}{-0.8}$