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60x-0.4x^2+5x+14=0

We add all the numbers together, and all the variables

-0.4x^2+65x+14=0

a = -0.4; b = 65; c = +14;

Δ = b^{2}-4ac

Δ = 65^{2}-4·(-0.4)·14

Δ = 4247.4

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-\sqrt{4247.4}}{2*-0.4}=\frac{-65-\sqrt{4247.4}}{-0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+\sqrt{4247.4}}{2*-0.4}=\frac{-65+\sqrt{4247.4}}{-0.8} $

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