# 50t-4t^2-120=0

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## Solution for 50t-4t^2-120=0 equation:

50t-4t^2-120=0
a = -4; b = 50; c = -120;Δ = b2-4acΔ = 502-4·(-4)·(-120)Δ = 580The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{145}}{2*-4}=\frac{-50-2\sqrt{145}}{-8}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{145}}{2*-4}=\frac{-50+2\sqrt{145}}{-8}$

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