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4x^2=2.8x+4.8

We move all terms to the left:

4x^2-(2.8x+4.8)=0

We get rid of parentheses

4x^2-2.8x-4.8=0

a = 4; b = -2.8; c = -4.8;

Δ = b^{2}-4ac

Δ = -2.8^{2}-4·4·(-4.8)

Δ = 84.64

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.8)-\sqrt{84.64}}{2*4}=\frac{2.8-\sqrt{84.64}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.8)+\sqrt{84.64}}{2*4}=\frac{2.8+\sqrt{84.64}}{8} $

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