4x^2=2.8x+4.8

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Solution for 4x^2=2.8x+4.8 equation:



4x^2=2.8x+4.8
We move all terms to the left:
4x^2-(2.8x+4.8)=0
We get rid of parentheses
4x^2-2.8x-4.8=0
a = 4; b = -2.8; c = -4.8;
Δ = b2-4ac
Δ = -2.82-4·4·(-4.8)
Δ = 84.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.8)-\sqrt{84.64}}{2*4}=\frac{2.8-\sqrt{84.64}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.8)+\sqrt{84.64}}{2*4}=\frac{2.8+\sqrt{84.64}}{8} $

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