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4x^2-70x+150=0

a = 4; b = -70; c = +150;

Δ = b^{2}-4ac

Δ = -70^{2}-4·4·150

Δ = 2500

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-50}{2*4}=\frac{20}{8} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+50}{2*4}=\frac{120}{8} =15 $

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