# 4x^2-70x+150=0

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## Solution for 4x^2-70x+150=0 equation:

4x^2-70x+150=0
a = 4; b = -70; c = +150;Δ = b2-4acΔ = -702-4·4·150Δ = 2500The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-50}{2*4}=\frac{20}{8} =2+1/2$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+50}{2*4}=\frac{120}{8} =15$

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