3z2=1.2

Solution for 3z2=1.2 equation:

3z^2=1.2

We move all terms to the left:

3z^2-(1.2)=0

We add all the numbers together, and all the variables

3z^2-1.2=0

a = 3; b = 0; c = -1.2;
Δ = b2-4ac
Δ = 02-4·3·(-1.2)
Δ = 14.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{14.4}}{2*3}=\frac{0-\sqrt{14.4}}{6}
=-\frac{\sqrt{}}{6}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{14.4}}{2*3}=\frac{0+\sqrt{14.4}}{6}
=\frac{\sqrt{}}{6}
$