2p^2+2p-12=-2p^2

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Solution for 2p^2+2p-12=-2p^2 equation:



2p^2+2p-12=-2p^2
We move all terms to the left:
2p^2+2p-12-(-2p^2)=0
We get rid of parentheses
2p^2+2p^2+2p-12=0
We add all the numbers together, and all the variables
4p^2+2p-12=0
a = 4; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·4·(-12)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*4}=\frac{-16}{8} =-2 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*4}=\frac{12}{8} =1+1/2 $

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