288=2x^2

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Solution for 288=2x^2 equation:



288=2x^2
We move all terms to the left:
288-(2x^2)=0
a = -2; b = 0; c = +288;
Δ = b2-4ac
Δ = 02-4·(-2)·288
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-2}=\frac{-48}{-4} =+12 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-2}=\frac{48}{-4} =-12 $

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