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15+7x=2x^2

We move all terms to the left:

15+7x-(2x^2)=0

determiningTheFunctionDomain -2x^2+7x+15=0

a = -2; b = 7; c = +15;

Δ = b^{2}-4ac

Δ = 7^{2}-4·(-2)·15

Δ = 169

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-13}{2*-2}=\frac{-20}{-4} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+13}{2*-2}=\frac{6}{-4} =-1+1/2 $

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