10m^2-45m+45=0

Solution for 10m^2-45m+45=0 equation:

10m^2-45m+45=0

a = 10; b = -45; c = +45;
Δ = b2-4ac
Δ = -452-4·10·45
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-15}{2*10}=\frac{30}{20}
=1+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+15}{2*10}=\frac{60}{20}
=3
$