# 0=-4.9t^2+9.8t

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## Solution for 0=-4.9t^2+9.8t equation:

0=-4.9t^2+9.8t
We move all terms to the left:
0-(-4.9t^2+9.8t)=0
We add all the numbers together, and all the variables
-(-4.9t^2+9.8t)=0
We get rid of parentheses
4.9t^2-9.8t=0
a = 4.9; b = -9.8; c = 0;Δ = b2-4acΔ = -9.82-4·4.9·0Δ = 96.04The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.8)-\sqrt{96.04}}{2*4.9}=\frac{9.8-\sqrt{96.04}}{9.8}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.8)+\sqrt{96.04}}{2*4.9}=\frac{9.8+\sqrt{96.04}}{9.8}$

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