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0=-4.9t^2+9.8t

We move all terms to the left:

0-(-4.9t^2+9.8t)=0

We add all the numbers together, and all the variables

-(-4.9t^2+9.8t)=0

We get rid of parentheses

4.9t^2-9.8t=0

a = 4.9; b = -9.8; c = 0;

Δ = b^{2}-4ac

Δ = -9.8^{2}-4·4.9·0

Δ = 96.04

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.8)-\sqrt{96.04}}{2*4.9}=\frac{9.8-\sqrt{96.04}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.8)+\sqrt{96.04}}{2*4.9}=\frac{9.8+\sqrt{96.04}}{9.8} $

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