# (90x-0.5x^2)-(50x+300)=1500

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## Solution for (90x-0.5x^2)-(50x+300)=1500 equation:

(90x-0.5x^2)-(50x+300)=1500
We move all terms to the left:
(90x-0.5x^2)-(50x+300)-(1500)=0
We get rid of parentheses
-0.5x^2+90x-50x-300-1500=0
We add all the numbers together, and all the variables
-0.5x^2+40x-1800=0
a = -0.5; b = 40; c = -1800;Δ = b2-4acΔ = 402-4·(-0.5)·(-1800)Δ = -2000Delta is less than zero, so there is no solution for the equation

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