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(90x-0.5x^2)-(50x+300)=1500

We move all terms to the left:

(90x-0.5x^2)-(50x+300)-(1500)=0

We get rid of parentheses

-0.5x^2+90x-50x-300-1500=0

We add all the numbers together, and all the variables

-0.5x^2+40x-1800=0

a = -0.5; b = 40; c = -1800;

Δ = b^{2}-4ac

Δ = 40^{2}-4·(-0.5)·(-1800)

Δ = -2000

Delta is less than zero, so there is no solution for the equation

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