7(5x+3)=7(x+5)-14+28x

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Solution for 7(5x+3)=7(x+5)-14+28x equation:


Simplifying
7(5x + 3) = 7(x + 5) + -14 + 28x

Reorder the terms:
7(3 + 5x) = 7(x + 5) + -14 + 28x
(3 * 7 + 5x * 7) = 7(x + 5) + -14 + 28x
(21 + 35x) = 7(x + 5) + -14 + 28x

Reorder the terms:
21 + 35x = 7(5 + x) + -14 + 28x
21 + 35x = (5 * 7 + x * 7) + -14 + 28x
21 + 35x = (35 + 7x) + -14 + 28x

Reorder the terms:
21 + 35x = 35 + -14 + 7x + 28x

Combine like terms: 35 + -14 = 21
21 + 35x = 21 + 7x + 28x

Combine like terms: 7x + 28x = 35x
21 + 35x = 21 + 35x

Add '-21' to each side of the equation.
21 + -21 + 35x = 21 + -21 + 35x

Combine like terms: 21 + -21 = 0
0 + 35x = 21 + -21 + 35x
35x = 21 + -21 + 35x

Combine like terms: 21 + -21 = 0
35x = 0 + 35x
35x = 35x

Add '-35x' to each side of the equation.
35x + -35x = 35x + -35x

Combine like terms: 35x + -35x = 0
0 = 35x + -35x

Combine like terms: 35x + -35x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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