40(b-1)+10=5(8b-6)

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Solution for 40(b-1)+10=5(8b-6) equation: 


Simplifying
40(b + -1) + 10 = 5(8b + -6)

Reorder the terms:
40(-1 + b) + 10 = 5(8b + -6)
(-1 * 40 + b * 40) + 10 = 5(8b + -6)
(-40 + 40b) + 10 = 5(8b + -6)

Reorder the terms:
-40 + 10 + 40b = 5(8b + -6)

Combine like terms: -40 + 10 = -30
-30 + 40b = 5(8b + -6)

Reorder the terms:
-30 + 40b = 5(-6 + 8b)
-30 + 40b = (-6 * 5 + 8b * 5)
-30 + 40b = (-30 + 40b)

Add '30' to each side of the equation.
-30 + 30 + 40b = -30 + 30 + 40b

Combine like terms: -30 + 30 = 0
0 + 40b = -30 + 30 + 40b
40b = -30 + 30 + 40b

Combine like terms: -30 + 30 = 0
40b = 0 + 40b
40b = 40b

Add '-40b' to each side of the equation.
40b + -40b = 40b + -40b

Combine like terms: 40b + -40b = 0
0 = 40b + -40b

Combine like terms: 40b + -40b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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