3(y+1)+2(y-3)=-28

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Solution for 3(y+1)+2(y-3)=-28 equation:


Simplifying
3(y + 1) + 2(y + -3) = -28

Reorder the terms:
3(1 + y) + 2(y + -3) = -28
(1 * 3 + y * 3) + 2(y + -3) = -28
(3 + 3y) + 2(y + -3) = -28

Reorder the terms:
3 + 3y + 2(-3 + y) = -28
3 + 3y + (-3 * 2 + y * 2) = -28
3 + 3y + (-6 + 2y) = -28

Reorder the terms:
3 + -6 + 3y + 2y = -28

Combine like terms: 3 + -6 = -3
-3 + 3y + 2y = -28

Combine like terms: 3y + 2y = 5y
-3 + 5y = -28

Solving
-3 + 5y = -28

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 5y = -28 + 3

Combine like terms: -3 + 3 = 0
0 + 5y = -28 + 3
5y = -28 + 3

Combine like terms: -28 + 3 = -25
5y = -25

Divide each side by '5'.
y = -5

Simplifying
y = -5

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