2m(b+5)+m(b+5)=

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Solution for 2m(b+5)+m(b+5)= equation:


Simplifying
2m(b + 5) + m(b + 5) = 0

Reorder the terms:
2m(5 + b) + m(b + 5) = 0
(5 * 2m + b * 2m) + m(b + 5) = 0

Reorder the terms:
(2bm + 10m) + m(b + 5) = 0
(2bm + 10m) + m(b + 5) = 0

Reorder the terms:
2bm + 10m + m(5 + b) = 0
2bm + 10m + (5 * m + b * m) = 0

Reorder the terms:
2bm + 10m + (bm + 5m) = 0
2bm + 10m + (bm + 5m) = 0

Reorder the terms:
2bm + bm + 10m + 5m = 0

Combine like terms: 2bm + bm = 3bm
3bm + 10m + 5m = 0

Combine like terms: 10m + 5m = 15m
3bm + 15m = 0

Solving
3bm + 15m = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-15m' to each side of the equation.
3bm + 15m + -15m = 0 + -15m

Combine like terms: 15m + -15m = 0
3bm + 0 = 0 + -15m
3bm = 0 + -15m
Remove the zero:
3bm = -15m

Divide each side by '3m'.
b = -5

Simplifying
b = -5

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