16(v+3)-4v=3(4v+2)-12

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Solution for 16(v+3)-4v=3(4v+2)-12 equation: 


Simplifying
16(v + 3) + -4v = 3(4v + 2) + -12

Reorder the terms:
16(3 + v) + -4v = 3(4v + 2) + -12
(3 * 16 + v * 16) + -4v = 3(4v + 2) + -12
(48 + 16v) + -4v = 3(4v + 2) + -12

Combine like terms: 16v + -4v = 12v
48 + 12v = 3(4v + 2) + -12

Reorder the terms:
48 + 12v = 3(2 + 4v) + -12
48 + 12v = (2 * 3 + 4v * 3) + -12
48 + 12v = (6 + 12v) + -12

Reorder the terms:
48 + 12v = 6 + -12 + 12v

Combine like terms: 6 + -12 = -6
48 + 12v = -6 + 12v

Add '-12v' to each side of the equation.
48 + 12v + -12v = -6 + 12v + -12v

Combine like terms: 12v + -12v = 0
48 + 0 = -6 + 12v + -12v
48 = -6 + 12v + -12v

Combine like terms: 12v + -12v = 0
48 = -6 + 0
48 = -6

Solving
48 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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