10+4(b-5)=3(b-10)

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Solution for 10+4(b-5)=3(b-10) equation:


Simplifying
10 + 4(b + -5) = 3(b + -10)

Reorder the terms:
10 + 4(-5 + b) = 3(b + -10)
10 + (-5 * 4 + b * 4) = 3(b + -10)
10 + (-20 + 4b) = 3(b + -10)

Combine like terms: 10 + -20 = -10
-10 + 4b = 3(b + -10)

Reorder the terms:
-10 + 4b = 3(-10 + b)
-10 + 4b = (-10 * 3 + b * 3)
-10 + 4b = (-30 + 3b)

Solving
-10 + 4b = -30 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-10 + 4b + -3b = -30 + 3b + -3b

Combine like terms: 4b + -3b = 1b
-10 + 1b = -30 + 3b + -3b

Combine like terms: 3b + -3b = 0
-10 + 1b = -30 + 0
-10 + 1b = -30

Add '10' to each side of the equation.
-10 + 10 + 1b = -30 + 10

Combine like terms: -10 + 10 = 0
0 + 1b = -30 + 10
1b = -30 + 10

Combine like terms: -30 + 10 = -20
1b = -20

Divide each side by '1'.
b = -20

Simplifying
b = -20

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