10(n+8)=2(40+5n)

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Solution for 10(n+8)=2(40+5n) equation:


Simplifying
10(n + 8) = 2(40 + 5n)

Reorder the terms:
10(8 + n) = 2(40 + 5n)
(8 * 10 + n * 10) = 2(40 + 5n)
(80 + 10n) = 2(40 + 5n)
80 + 10n = (40 * 2 + 5n * 2)
80 + 10n = (80 + 10n)

Add '-80' to each side of the equation.
80 + -80 + 10n = 80 + -80 + 10n

Combine like terms: 80 + -80 = 0
0 + 10n = 80 + -80 + 10n
10n = 80 + -80 + 10n

Combine like terms: 80 + -80 = 0
10n = 0 + 10n
10n = 10n

Add '-10n' to each side of the equation.
10n + -10n = 10n + -10n

Combine like terms: 10n + -10n = 0
0 = 10n + -10n

Combine like terms: 10n + -10n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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