1(t-4)+7t=4(2t+5)-13

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Solution for 1(t-4)+7t=4(2t+5)-13 equation:


Simplifying
1(t + -4) + 7t = 4(2t + 5) + -13

Reorder the terms:
1(-4 + t) + 7t = 4(2t + 5) + -13
(-4 * 1 + t * 1) + 7t = 4(2t + 5) + -13
(-4 + 1t) + 7t = 4(2t + 5) + -13

Combine like terms: 1t + 7t = 8t
-4 + 8t = 4(2t + 5) + -13

Reorder the terms:
-4 + 8t = 4(5 + 2t) + -13
-4 + 8t = (5 * 4 + 2t * 4) + -13
-4 + 8t = (20 + 8t) + -13

Reorder the terms:
-4 + 8t = 20 + -13 + 8t

Combine like terms: 20 + -13 = 7
-4 + 8t = 7 + 8t

Add '-8t' to each side of the equation.
-4 + 8t + -8t = 7 + 8t + -8t

Combine like terms: 8t + -8t = 0
-4 + 0 = 7 + 8t + -8t
-4 = 7 + 8t + -8t

Combine like terms: 8t + -8t = 0
-4 = 7 + 0
-4 = 7

Solving
-4 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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