0=-x2-8x-12

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Solution for 0=-x2-8x-12 equation:



0=-x2-8x-12
We move all terms to the left:
0-(-x2-8x-12)=0
We add all the numbers together, and all the variables
-(-1x^2-8x-12)+0=0
We add all the numbers together, and all the variables
-(-1x^2-8x-12)=0
We get rid of parentheses
1x^2+8x+12=0
We add all the numbers together, and all the variables
x^2+8x+12=0
a = 1; b = 8; c = +12;
Δ = b2-4ac
Δ = 82-4·1·12
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4}{2*1}=\frac{-12}{2} =-6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4}{2*1}=\frac{-4}{2} =-2 $

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