-(4y+1)-(-3y-4)=3

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Solution for -(4y+1)-(-3y-4)=3 equation:


Simplifying
-1(4y + 1) + -1(-3y + -4) = 3

Reorder the terms:
-1(1 + 4y) + -1(-3y + -4) = 3
(1 * -1 + 4y * -1) + -1(-3y + -4) = 3
(-1 + -4y) + -1(-3y + -4) = 3

Reorder the terms:
-1 + -4y + -1(-4 + -3y) = 3
-1 + -4y + (-4 * -1 + -3y * -1) = 3
-1 + -4y + (4 + 3y) = 3

Reorder the terms:
-1 + 4 + -4y + 3y = 3

Combine like terms: -1 + 4 = 3
3 + -4y + 3y = 3

Combine like terms: -4y + 3y = -1y
3 + -1y = 3

Add '-3' to each side of the equation.
3 + -3 + -1y = 3 + -3

Combine like terms: 3 + -3 = 0
0 + -1y = 3 + -3
-1y = 3 + -3

Combine like terms: 3 + -3 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0

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