(x-3)2-(2x+5)2=-16

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Solution for (x-3)2-(2x+5)2=-16 equation: 


Simplifying
(x + -3) * 2 + -1(2x + 5) * 2 = -16

Reorder the terms:
(-3 + x) * 2 + -1(2x + 5) * 2 = -16

Reorder the terms for easier multiplication:
2(-3 + x) + -1(2x + 5) * 2 = -16
(-3 * 2 + x * 2) + -1(2x + 5) * 2 = -16
(-6 + 2x) + -1(2x + 5) * 2 = -16

Reorder the terms:
-6 + 2x + -1(5 + 2x) * 2 = -16

Reorder the terms for easier multiplication:
-6 + 2x + -1 * 2(5 + 2x) = -16

Multiply -1 * 2
-6 + 2x + -2(5 + 2x) = -16
-6 + 2x + (5 * -2 + 2x * -2) = -16
-6 + 2x + (-10 + -4x) = -16

Reorder the terms:
-6 + -10 + 2x + -4x = -16

Combine like terms: -6 + -10 = -16
-16 + 2x + -4x = -16

Combine like terms: 2x + -4x = -2x
-16 + -2x = -16

Add '16' to each side of the equation.
-16 + 16 + -2x = -16 + 16

Combine like terms: -16 + 16 = 0
0 + -2x = -16 + 16
-2x = -16 + 16

Combine like terms: -16 + 16 = 0
-2x = 0

Solving
-2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-2'.
x = 0

Simplifying
x = 0

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