(x+2)(8x+3)=3x-3

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Solution for (x+2)(8x+3)=3x-3 equation:



(x+2)(8x+3)=3x-3
We move all terms to the left:
(x+2)(8x+3)-(3x-3)=0
We get rid of parentheses
(x+2)(8x+3)-3x+3=0
We multiply parentheses ..
(+8x^2+3x+16x+6)-3x+3=0
We get rid of parentheses
8x^2+3x+16x-3x+6+3=0
We add all the numbers together, and all the variables
8x^2+16x+9=0
a = 8; b = 16; c = +9;
Δ = b2-4ac
Δ = 162-4·8·9
Δ = -32
Delta is less than zero, so there is no solution for the equation

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