(r+4r-3)+1(2r+4)=

Solution for (r+4r-3)+1(2r+4)= equation:

Simplifying
(r + 4r + -3) + 1(2r + 4) = 0

Reorder the terms:
(-3 + r + 4r) + 1(2r + 4) = 0

Combine like terms: r + 4r = 5r
(-3 + 5r) + 1(2r + 4) = 0

Remove parenthesis around (-3 + 5r)
-3 + 5r + 1(2r + 4) = 0

Reorder the terms:
-3 + 5r + 1(4 + 2r) = 0
-3 + 5r + (4 * 1 + 2r * 1) = 0
-3 + 5r + (4 + 2r) = 0

Reorder the terms:
-3 + 4 + 5r + 2r = 0

Combine like terms: -3 + 4 = 1
1 + 5r + 2r = 0

Combine like terms: 5r + 2r = 7r
1 + 7r = 0

Solving
1 + 7r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 7r = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 7r = 0 + -1
7r = 0 + -1

Combine like terms: 0 + -1 = -1
7r = -1

Divide each side by '7'.
r = -0.1428571429

Simplifying
r = -0.1428571429