(W-5)/2-3=(w-5)/5

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Solution for (W-5)/2-3=(w-5)/5 equation: 


x in (-oo:+oo)

(W-5)/2-3 = (w-5)/5 // - (w-5)/5

(W-5)/2-((w-5)/5)-3 = 0

(W-5)/2+(-1*(w-5))/5-3 = 0

(5*(W-5))/(2*5)+(-1*2*(w-5))/(2*5)+(-3*2*5)/(2*5) = 0

5*(W-5)-1*2*(w-5)-3*2*5 = 0

5*W-2*w-30-15 = 0

5*W-2*w-45 = 0

(5*W-2*w-45)/(2*5) = 0

(5*W-2*w-45)/(2*5) = 0 // * 2*5

5*W-2*w-45 = 0

x belongs to the empty set

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